- 1 Direction Sense Test with Basic Concepts and Tricks
- 2 Main Directions
- 3 Secondary Directions
- 4 Example 1 – Applying Main Direction
- 5 Example 2 – Applying Pythagoras Theorem
- 6 Example 3 – Applying Main Direction
- 7 Example 4 – Applying Secondary Direction
- 8 Example 5 – Applying Main Direction
- 9 Example 6 – Applying Main Direction
Direction Sense Test with Basic Concepts and Tricks
Today we are going to discuss an important chapter of reasoning i.e. Direction Sense Test with Basic Concepts and Tricks. Usually, 2-5 questions in the reasoning ability paper may have direction test (also called direction sense) based questions.
Students are required to analyse the given information pertaining to the movement of vehicles, persons etc., and then find the solution to given problems.
The figure given below shows four main directions – East, West, North and South.
There are four secondary directions – North-East (N-E), North-West (N-W), South-East (S-E), and South-West (S-W) as shown below:
i) At the time of sunrise if a man stands facing the east, his shadow will be towards west.
ii) At the time of sunset the shadow of an object is always in the east.
iii) If a man stands facing the North, at the time of sunrise his shadow will be towards his left and at the time of sunset it will be towards his right.
iv) At 12:00 noon, the rays of the sun are vertically downward hence there will be no shadow.
Example 1 – Applying Main Direction
Hemanth is starting from his house, goes 5km in the East, then he turns to his left and goes 4 km. Finally he turns to his left and goes 5 km. Now how far is he from his house and in what direction?
From this figure it is clear that Hemanth is 4 km from his house and is in North direction.
Example 2 – Applying Pythagoras Theorem
Surma starting from hers house, goes 4 km in the East, then she turns to hers right and goes 3 km. What minimum distance will be covered by Suma to come back to her house?
Applying Pythagoras theorem
Minimum distance =√(42+32)
Example 3 – Applying Main Direction
Rohan walks 5 km towards North. Then he turns towards right and walks 3 km. Then he again turns to his right and moves 5 km. How far is he from the starting point?
a) 10 km
b) 13 km
c) 15 km
d) 8 km
e) 3 km
The movements can be sketched in the form of adjacent diagram.
Consider A as starting points and B as final point.
Shortest distance between A and B is 3 km.
Answer : → e) 3 km
i) Always indicate the path joining initial and final position with a dotted line. This is the shortest distance between the starting point and the final point.
ii) Consider the distance to be in a straight line.
iii) Consider the turn ( Left or Right ) as 90° turn.
Example 4 – Applying Secondary Direction
Sanjay walks 7 km towards North and turns towards left and covers 3 km. Again he turns towards left and walks 11 km. How far is he form the starting point?
a) 16 km
b) 21 km
c) 12 km
d) 5 km
e) 8 km
Sanjay started form A and walks 7 km North up to B, turns towards left (West) and goes 3 km to C and walks towards left (South) and walks 11 km and reaches point E.
Now DA = CB = 3 km
DC = AB = 7 km
DE = 11 – DC = 4 km
DA = 3 km
DE = 4 km
EA = √(DE2+DA2)
EA = √(42+32)
Answer : → d) 5 km
Example 5 – Applying Main Direction
Sushma walks 20 meters towards North. Then she turns right and walks 30 meters. Now, she turns right and walks 35 meters. Now turning left, she walks 15 meters. Again she turns left and moves 15 meters. Finally, she turns left and walks 15 meters. In which direction and how far is she form her original position?
a) 15 meters East
b) 30 meters East
c) 15 meters West
d) 45 meters West
e) None of these
Sushma starts form A and after all the movements as per the directions given in the problem; she finally reaches the destination B. Now, she is at a distance of 30 meters in the Eastern direction form her starting point.
Answer: → b) 30 meters East
Example 6 – Applying Main Direction
Akshatha walks 10 meters facing the early morning Sun and goes 10 meters to the right. She then walks 5, 15 and 15 meters, each time turning to her left. How far is she now form her starting point?
a) 10 meters
b) 15 meters
c) 20 meters
d) 5 meters
e) None of these
A is the starting point.
G is the final point.
DF = 15 meters.
DE = CB = 10 meters.
EF = DF – DE = 15 – 10 = 5 meters.
AG = EF = 5 meters
Answer : → d) 5 meters
If you get any difficulties in this chapter you can comment below. We try to solve your problem here.